#ASSAY OF ATROPINE


Aim: To report the amount of atropine present in the given tablet/powder/solution
.
Materials: Burettes, pipettes, beakers, glassrod, funneletc

Chemicals: Perchloricacid, glacial acetic acid, PHP, Atropine sulphate

Principle:
            Assay of Atropine comes under non aqueous titration. Weak bases are dissolved in acetic acid and titrated with perchloricacid. Acetic acid which is frequently used as a solvent for titration of basic substances in non-aqueous titration. When strong acid like perchloric acid dissolve in acetic acid combines with protons donated by perchloricacid to form acetonium ion. Atropine in acetic acid exerts leveling effect and enhance basic property, accept a proton from acetonium ion forms protonated atropine and acetic acid. Crystal violet is used as an indicator.



Procedure:
Standardization of 0.1M Perchloric acid

Place 0.02 gm of PHP in 100ml conical flask, dissolve in 10 ml GAA and add one drop of crystal violet solution and titrate against 0.1 M HClO4.
  
Equivalent factor: Each ml of 0.1M HClO4® 0.02042 gm of PHP.
Assay.
         Weigh accurately about 0.5 g, dissolve in 30 ml of anhydrous glacial acetic acid. Titrate with 0.1 M perchloricacid, determine the end-point potentiometrically Carry out a blank titration.
          1 ml of 0.1 M perchloricacid is equivalent to 0.06768 g of (C17H23NO3)2, H 2SO4.
Calculations:
Standardisation of 0.1M Perchloric acid
S. No
Contents in the flask
Burette Reading
Volume Consumed
Indicator
Initial
Final
1





2






Each ml of 0.1M HClO≡ 0.02042 gm of PHP.
                                X ml of Y M of HClO≡ gms of PHP.
                                                            Y =






Assay:
S. No
Contents of the flask
Burette reading
Volume consumed
Indicator
Initial
Final
1






1ml of 0.1M HClO≡ 0.06768 g of (C17H23NO3)2, H 2SO4.

X ml of Y M HClO4 ≡ Z gm of (C17H23NO3)2, H 2SO4
Z=

Percentage purity = Estimate amount / Weight of powder taken
Report: The percent purity of Atropine sulphate present in given sample is found to be

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